If it's not what You are looking for type in the equation solver your own equation and let us solve it.
45b^2-10b=0
a = 45; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·45·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*45}=\frac{0}{90} =0 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*45}=\frac{20}{90} =2/9 $
| (3r+4)^2=-8 | | 5r^2-2=34 | | 40a+15a^2=0 | | 81x-5x=10x+21 | | 12s^2+9=12s | | 6p+12p^2=0 | | (39x^2-476x-2461)/78657=0 | | 7u^2+1=29 | | 20x^2±35x=0 | | 1/4x-2=6+5/12x | | 8x+43=65 | | -7n^2=448 | | 15y-2-3y=7 | | -60+15x=10+x | | 3/x=5/100 | | 5x+(x+6)-x=5x-10 | | 4x-9+5=2-2x | | X-3=+9-x | | 8x+1=-31x= | | 4x+2(×-3)=3x+x-12 | | 7^-7x=9 | | 5x^2-7=448 | | 2x^2+23x=25 | | 4x2-250=0 | | 1.2=10-x-10x/100 | | -2+6y-7=0 | | 3x2–12x–7=0 | | -26-x=-17,6-3x | | 6/7=10/x | | 3y=1/27 | | -4.9t^2+44.1t+1=0 | | x+(2/3*x)=120 |